


is constant, implies:
.
is negligibly small, the rate of formation of D is essentially equal to the rate of disappearance of A, and the rate of change of
can be set equal to zero. Applying the steady state approximation
(
)
allows the elimination of
from the kinetic equations, whereupon the rate of reaction is expressed:

is even approximately constant, only that its absolute rate of change is very much smaller than that of
and
. Since according to the reaction scheme
,
the assumption that
is constant would lead, for the case in which C is in large excess, to the absurd conclusion that formation of the product D will continue at a constant rate even after the reactant A has been consumed.